If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x^2 = 0
x = 0
x = 0
x^2 = 0
x^2 = 0
1*x^2 = 0 // : 1
x^2 = 0
x = 0
x in (-oo:0) U (0:+oo)
24/(x^2)-(3/x)-16+4 = 2/x+4 // - 2/x+4
24/(x^2)-(3/x)-(2/x)-16-4+4 = 0
24/(x^2)-3*x^-1-2*x^-1-16-4+4 = 0
24*x^-2-5*x^-1-16 = 0
t_1 = x^-1
24*t_1^2-5*t_1^1-16 = 0
24*t_1^2-5*t_1-16 = 0
DELTA = (-5)^2-(-16*4*24)
DELTA = 1561
DELTA > 0
t_1 = (1561^(1/2)+5)/(2*24) or t_1 = (5-1561^(1/2))/(2*24)
t_1 = (1561^(1/2)+5)/48 or t_1 = (5-1561^(1/2))/48
t_1 = (5-1561^(1/2))/48
x^-1-((5-1561^(1/2))/48) = 0
1*x^-1 = (5-1561^(1/2))/48 // : 1
x^-1 = (5-1561^(1/2))/48
-1 < 0
1/(x^1) = (5-1561^(1/2))/48 // * x^1
1 = ((5-1561^(1/2))/48)*x^1 // : (5-1561^(1/2))/48
48*(5-1561^(1/2))^-1 = x^1
x = 48*(5-1561^(1/2))^-1
t_1 = (1561^(1/2)+5)/48
x^-1-((1561^(1/2)+5)/48) = 0
1*x^-1 = (1561^(1/2)+5)/48 // : 1
x^-1 = (1561^(1/2)+5)/48
-1 < 0
1/(x^1) = (1561^(1/2)+5)/48 // * x^1
1 = ((1561^(1/2)+5)/48)*x^1 // : (1561^(1/2)+5)/48
48*(1561^(1/2)+5)^-1 = x^1
x = 48*(1561^(1/2)+5)^-1
x in { 48*(5-1561^(1/2))^-1, 48*(1561^(1/2)+5)^-1 }
| -1/5x-2=-20 | | w=5(3)+5 | | 34=-(8n-4)-5(6n-6) | | 1=10 | | -4(v-1)=16-2v | | 2-a-(-b)+c+(-a)-b-(-c)=0 | | 12*11-(15-9)/3-(9-6) | | 4x-3y=32 | | b+3/2b+(b+45)+(2b-90)+90=560 | | 3(x+4)-4=8 | | 4a+2=36-5 | | 12X11(15-9)/3-(9-6) | | -3.6-r=-(-6r+0.6) | | 8x^2-2xy+7y^2=8 | | 9(84)=9 | | -3c+7a+5+17b+2c+2c+b+(-7a)=0 | | 4(2x-7)+33=-5(x-5)+17x-28 | | -5(-2x+2)=-9x | | -7x-3y=-7 | | 6st+9t+10s-15= | | -32-7x=4(4x-8) | | -3.6-r=(-6r+0.6) | | 4+4x-x^2-x^3=0 | | 3x-15+x=180 | | -6-2(-9x-8)=-3 | | s=q+3/x | | .40c+4-.20c=-9 | | -23=-t | | b-4c+3a-c-9b-4a=0 | | 5(6x-5)+51=-6(x-7)+18x+2 | | -8x-9+5x=-9x+3 | | x+3=5x+2 |